• MonkderVierte@lemmy.zip
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    10 hours ago

    So, googling it, the general premise is you should use smart pointers instead to avoid crashes. Got it.

      • MonkderVierte@lemmy.zip
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        6 hours ago

        Unlike many other programming languages, which are often picked up on the go from tutorials found on the Internet, few are able to quickly pick up C++ without studying a well-written C++ book. It is way too big and complex for doing this. In fact, it is so big and complex, that there are very many very bad C++ books out there. And we are not talking about bad style, but things like sporting glaringly obvious factual errors and promoting abysmally bad programming styles.

        https://stackoverflow.com/questions/388242/the-definitive-c-book-guide-and-list

        • mnemonicmonkeys@sh.itjust.works
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          6 hours ago

          Considering that most of the “answers” I’ve found on StackOverflow were complete dogshit, I’m wary of this reading list

    • Susaga@sh.itjust.works
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      21 hours ago

      I think int*** is meant to be pointing at int**, but the image is just unclear about where everything is in perspective.

      • dohpaz42@lemmy.world
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        18 hours ago

        Pretty sure the image is clear:

        int*** -> int*
        int** -> int
        Int* -> int
        

        Clarity doesn’t mean correct. But that’s probably why it’s posted here. 🤷‍♂️

        • Susaga@sh.itjust.works
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          8 hours ago

          RT*** isn’t pointing at RT*, he’s pointing at the TV showing RT**. The fact you think otherwise is what makes the image unclear. I’m not sure why you insist on them being wrong.

        • mexicancartel@lemmy.dbzer0.com
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          13 hours ago

          int** is inside a TV, and persumably int* must be inside another TV(even though uts not edited in). The image perespective is showing one thing inside the other, inside the other. So when when int*** points the TV it reference int**, which reference int* which reference int. Its just edited very bad

    • ジン@quokk.au
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      18 hours ago

      That’s not the end of the chain either, right?

      Because : int -> &int -> &&int

      Or can you not use the address operator like that? It also might be int& &, I failed cs2200 on this exact type of technicality

    • dejected_warp_core@lemmy.world
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      1 hour ago

      *x = dereference or “point to”. Treats the variable x as containing a pointer value. Evaluates to a variable existing at the address in x.

      &x = reference or “get address of”. Evaluates to the address of x.

      They’re complimentary operators, so *(&x) cancels out and is equvalent to just x.

    • ZILtoid1991@lemmy.worldOP
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      12 hours ago

      The & operator references the value.

      int i;
      int* p = &i;
      

      In C++, the & at the function argument makes it a reference type (safe pointer).

      void someFunction(int& refVal) {
          [...]
      }
      
      • Flames5123@sh.itjust.works
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        11 hours ago

        As someone who likes working with higher level languages, I never understood the pass by reference or even referencing different pointers. It never stuck out to me as useful in what I want software to do. It’s too close to hardware.

        • Sylvartas@lemmy.dbzer0.com
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          7 hours ago

          Most of the time you pass by reference for more outputs, or by const ref to avoid copying a big-ass data structure (which is not always straightforward, with structures smaller than a pointer, which are pretty big in 64 bits architecture, you lose more to the ref overhead than to the copy IIRC)

          • DahGangalang@infosec.pub
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            7 hours ago

            Another reason I commonly see: to change the structure / “main pointer” to a data structure (esp during freeing and cleanup).

        • lime!@feddit.nu
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          9 hours ago

          if you’re working with higher level languages you pass-by-reference all the time. give a list to a function to modify it? that’s by reference. giving an event handler function to a framework? that’s by reference. setting a property on an object? that’s usually by reference.

          • funkless_eck@sh.itjust.works
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            9 hours ago

            the list is the helpful part to understanding it.

            it would be terrible if, with bar being a list and foo being a member of the list

             if foo in bar: return true
            

            modified the list. So yeah, you want to look at the list not edit the list, it’s a pointer.

            • Sylvartas@lemmy.dbzer0.com
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              6 hours ago

              A pointer to the list would allow you to modify whatever’s at that pointer’s address though. If you want to look at the list and not edit it you pass by const reference 99% of the time (or you pass a copy) and if your language doesn’t have that I don’t like it.

              • captcha_incorrect@lemmy.world
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                5 hours ago

                I still don’t get the point of pointers.

                I want my language to pass by reference. I give a variable to a function and the variable in the function scope should be a reference to the same place in memory as the original variable.

                How can pointers help me here? What value does it provide? Genuine question.

                • Sylvartas@lemmy.dbzer0.com
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                  4 hours ago

                  I want my language to pass by reference. I give a variable to a function and the variable in the function scope should be a reference to the same place in memory as the original variable.

                  I’m not even a C++ wizard or anything (though it’s my most advanced language) so I’m not gonna argue that is good or bad, that sounds fine to me for a wide range of applications already.

                  But the way is see it, pointers kinda allow you to use “raw memory” which is an actual thing that’s gonna be handled by the program one way or another, and it’s a way to relatively refer to memory for example. As some guy on stackoverflow put it “That guy at the end for the bar” vs “Bob” can be very useful. Especially when using data structures you don’t know the size of at compile time.

            • gerryflap@feddit.nl
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              7 hours ago

              Your example doesn’t make sense to me. Why would you modify the entire list by checking if something is in it? Also, you can totally edit the list via a pointer, that’s how you’re supposed to edit the list if you want any performance. Otherwise you’d be copying the list on every modification, which is terribly inefficient

            • lime!@feddit.nu
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              9 hours ago

              other way round surely? if you want to modify the original object, use a pointer. if you don’t, use a copy.

        • ZILtoid1991@lemmy.worldOP
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          10 hours ago

          Reference values are quite useful, such as:

          double valOut;
          if (parseDouble(valOut) == 0) { //Argument of parseDouble is ref type, no & needed for input, no exceptions needed for error handling
              [...] //No error, code executed normally
          } else {
              [...] //Erroreus input
          }
          
        • palordrolap@fedia.io
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          7 hours ago

          In the C programming language. Or do you mean which C project specifically? Because as Technus surmises in their response, it’s usually a better idea to set up aliases (typedefs or heck, even #defines) so that you’re offloading some of the mental strain keeping track of the layers, and that’s likely to be what happens in production code.

          But the underlying data type is still T***.

      • Technus@lemmy.zip
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        20 hours ago

        Ah right, so that would be a 3D array.

        • T* is a single row of T
        • T** is a list of rows
        • T*** is a list of “layers” in the third dimension

        This would be incredibly hazardous to pass around as a bare pointer with no context, though. I’d expect to see this in a struct that, at minimum, also includes fields for the size of each dimension.

  • Deconceptualist@leminal.space
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    17 hours ago

    The placement of the labels is a bit sloppy but I think it tracks. The character in the middle (int*) is pointing at int, then the one on the left (int**) is pointing at the middle one (int*), etc

    What I want to know: what is that shirt and where do I get it?

    • addie@feddit.uk
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      10 hours ago

      He dereferenced a pointer to the 1970s and retrieved the shirt that way.

  • 14th_cylon@lemmy.zip
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    21 hours ago

    Why should the left one in the rectangle be int**? It doesn’t make sense to me, they are both clearly just int*

    What am i missing?